Mathematics ยท WME01 (M1)
Constant acceleration (suvat)
When acceleration is constant, five quantities are linked by five equations.
The letters
s = displacement (m), u = initial velocity (m/s), v = final velocity (m/s), a = acceleration (m/s2), t = time (s).
The equations
- v = u + at
- s = (u + v)t / 2
- v2 = u2 + 2as
- s = ut + (1/2)at2
- s = vt - (1/2)at2
Pick the one that leaves out the quantity you neither know nor want.
Signs
Choose a positive direction and stick to it. For vertical motion under gravity, use g = 9.8 m/s2 (the value Pearson uses unless told otherwise), with the sign set by your positive direction.
Worked example
A car accelerates from 4 m/s at 2 m/s2 for 5 s. How far does it travel?
- u = 4, a = 2, t = 5, want s.
- s = ut + (1/2)at2 = 20 + 25
Answer: s = 45 m
Check yourself
- u = 3 m/s, a = 2 m/s2, t = 4 s. Find v.
Show answer
11 m/s. v = u + at = 3 + 8 = 11 m/s.
- A particle starts from rest and accelerates at 4 m/s2 for 3 s. Find s.
Show answer
18 m. s = ut + (1/2)at2 = 0 + 18 = 18 m.
- u = 6 m/s, a = 2 m/s2, s = 7 m. Find v.
Show answer
8 m/s. v2 = 36 + 28 = 64, so v = 8 m/s.
- A car slows from 20 m/s to rest in 5 s. Find its acceleration.
Show answer
-4 m/s2. a = (v - u)/t = (0 - 20)/5 = -4 m/s2 (a deceleration of 4).
- You know u, a and t and want s. Which equation do you use?
- v2 = u2 + 2as
- v = u + at
- s = ut + (1/2)at2
- s = vt - (1/2)at2
Show answer
s = ut + (1/2)at2. It contains s, u, a and t and leaves out v.
Sources
Last updated 7 November 2026. Spotted a mistake? Email alevel@lifereadysociety.com.