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Variability: range, standard deviation and error bars

Edexcel IAL Biology · WBI13 Practical Skills in Biology I

A mean on its own says nothing about how spread out the repeats were. Range and standard deviation describe variability and let you judge whether a difference between means is likely to be real.

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Range and standard deviation

s = √[ Σ(x - x̄)² / (n - 1) ]

where x̄ is the mean and n the number of values. This is the sample standard deviation (divide by n - 1), the version Pearson uses. The formula is given in the paper when a calculation is needed, sometimes in the equivalent form s = √[ (Σx² - (Σx)²/n) / (n - 1) ]. On a calculator use the sₓ (σₙ₋₁) key, not σₓ (σₙ), which divides by n and gives a smaller answer.

About 68% of normally distributed data lie within one standard deviation of the mean, and about 95% within two.

Calculating s step by step

1. Find the mean x̄.

2. Subtract the mean from each value: (x - x̄).

3. Square each difference: (x - x̄)².

4. Add them: Σ(x - x̄)².

5. Divide by n - 1.

6. Square root.

Set out a table of x, (x - x̄) and (x - x̄)² to avoid slips.

xx - x̄(x - x̄)²
12-11
1524
11-24
1411
1300
Σ010

Data 12, 15, 11, 14, 13: mean 13

Error bars and overlap

Plot mean ± 1 standard deviation (or range bars) as vertical bars on a graph.

The June 2024 mark scheme: to show results are repeatable, repeat for every group, calculate means and standard deviations, and plot means with standard deviation bars.

Worked example

Calculate the standard deviation of 12, 15, 11, 14, 13.

  1. Mean = 65 / 5 = 13
  2. Squared differences: 1, 4, 4, 1, 0; sum = 10
  3. Divide by n - 1 = 4: 2.5
  4. s = √2.5 = 1.58

Answer: s = 1.58 (3 s.f.: 1.58)

Key idea: Range = max - min. s = √[Σ(x - x̄)² / (n - 1)]. Small s = repeatable data. Overlapping ±1 s error bars suggest a difference may be due to chance; a statistical test decides.

Check yourself

  1. Repeat readings are 2.3, 2.9, 2.6, 2.4 cm³. Calculate the range.
    Show answer

    0.6 cm³. 2.9 - 2.3 = 0.6 cm³.

  2. Calculate the standard deviation of 4, 6, 8, 10 using s = √[Σ(x - x̄)² / (n - 1)]. Give your answer to 3 significant figures.
    Show answer

    2.58. Mean 7; squared differences 9, 1, 1, 9 = 20; 20 / 3 = 6.67; √6.67 = 2.58.

  3. Zones of inhibition were 18, 20, 19, 21 and 17 mm. Calculate the standard deviation to 3 significant figures.
    Show answer

    1.58 mm. Mean 19; squared differences 1, 1, 0, 4, 4 = 10; 10 / 4 = 2.5; s = 1.58 mm.

  4. For the data 3, 5, 7, what is Σ(x - x̄)²?
    Show answer

    8. Mean 5; (−2)² + 0² + 2² = 8.

  5. Two groups have the same mean, but group A has a much smaller standard deviation. What does this show?
    • Group A's mean is more accurate
    • Group A's values are closer to the mean, so more repeatable
    • Group A has fewer values
    • Group B's results are wrong
    Show answer

    Group A's values are closer to the mean, so more repeatable. Smaller s means less spread.

  6. Error bars (mean ± 1 SD) for two treatments overlap a lot. What is the best conclusion?
    • The treatments definitely have the same effect
    • The difference is definitely significant
    • The experiment has no anomalies
    • The difference between the means may be due to chance
    Show answer

    The difference between the means may be due to chance. Overlap suggests no significant difference, but a test is needed to be sure.

  7. A question asks how to show that results are repeatable. Which answer is best?
    • Use a different method
    • Repeat each treatment several times, calculate means and standard deviations, and plot means with SD bars
    • Record results to more decimal places
    • Do the experiment once at a higher temperature
    Show answer

    Repeat each treatment several times, calculate means and standard deviations, and plot means with SD bars. This matches the June 2024 mark scheme.

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Last updated 8 November 2026. Spotted a mistake? Tell us.