All subjects · Biology · WBI16 Practical Skills in Biology II

Skills applied: CP11 ecology of a habitat

Edexcel IAL Biology · WBI16 Practical Skills in Biology II

CP11 is the field practical. Questions test sampling strategy, measuring abundance and abiotic factors, sample size, and Spearman's rank analysis.

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Sampling strategy

Method recap (see Core practical 11, Unit 4):

Measuring abundance and abiotic factors

Analysis

Worked example

12 quadrats of 0.25 m² contained 18, 22, 15, 20, 19, 25, 16, 21, 17, 23, 24, 20 daisies. Estimate the population in a 50 m² field.

  1. Total = 240 daisies in 12 x 0.25 = 3 m²
  2. Density = 80 per m²
  3. Population = 80 x 50 = 4000

Answer: About 4000 daisies.

Key idea: Random sampling for uniform areas, transects for gradients; enough quadrats when the running mean levels off. Percentage cover, density or frequency; abiotic readings at each quadrat with calibrated meters. Spearman's rank for correlations, chi-squared for distribution.

Check yourself

  1. When should a belt transect be used rather than random quadrats?
    • When the area is uniform
    • When there is no time
    • When an abiotic factor changes across the area, such as from shade to open ground
    • When only one species is present
    Show answer

    When an abiotic factor changes across the area, such as from shade to open ground. Transects sample along a gradient.

  2. How are random quadrat positions chosen?
    • Using random number coordinates on a grid laid over the area
    • Throwing the quadrat over your shoulder
    • Placing them where most plants grow
    • Placing them in a straight line
    Show answer

    Using random number coordinates on a grid laid over the area. Random coordinates avoid bias.

  3. 8 quadrats, each 0.5 m², contain a total of 96 snails. Calculate the mean density per m².
    Show answer

    24 per m². Area = 4 m²; 96 / 4 = 24 per m².

  4. A species was present in 14 of 40 quadrats. Calculate its percentage frequency.
    Show answer

    35 %. 14 / 40 x 100 = 35%.

  5. Along a transect of 7 quadrats, Σd² for soil moisture against moss cover is 6. Calculate rₛ to 3 decimal places.
    Show answer

    0.893. 1 - 36 / 336 = 0.893.

  6. For the moss data, rₛ = 0.893 with 7 pairs (critical value 0.786 at p = 0.05). What is the conclusion?
    • Accept the null hypothesis: no significant correlation
    • Reject the null hypothesis: a significant positive correlation between soil moisture and moss cover
    • There is a significant negative correlation
    • There is a significant difference between means
    Show answer

    Reject the null hypothesis: a significant positive correlation between soil moisture and moss cover. 0.893 > 0.786.

  7. How can you decide whether enough quadrats have been used?
    • Stop after three quadrats
    • Use one large quadrat
    • Count until you are tired
    • Plot a running mean against number of quadrats and check it has levelled off
    Show answer

    Plot a running mean against number of quadrats and check it has levelled off. A stable running mean shows the sample is representative.

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Last updated 8 November 2026. Spotted a mistake? Tell us.