All subjects · Biology · WBI16 Practical Skills in Biology II
Skills applied: CP17 spirometer traces, CP18 amylase in cereal grains
Edexcel IAL Biology · WBI16 Practical Skills in Biology II
CP17 asks you to read a spirometer trace; CP18 asks you to measure amylase activity from cereal grains. Both appear in planning and data questions with ethics or aseptic technique.
CP17: reading a spirometer trace
Method recap (see Core practical 17, Unit 5): a volunteer breathes from a chamber of medical oxygen through soda lime (absorbs CO₂); the trace records volume against time.
- Tidal volume: height of one normal breath (peak to trough).
- Breathing rate: number of peaks per minute.
- Minute ventilation = tidal volume x breathing rate.
- Vital capacity: from the deepest breath in to the deepest breath out.
- Oxygen consumption: the trace drifts downwards as O₂ is used (CO₂ is absorbed); oxygen consumption rate = fall in the trace ÷ time.
After exercise, tidal volume, breathing rate and oxygen consumption rise.
Ethics and safety: informed consent, medical screening, sterile mouthpiece, fresh soda lime, nose clip, stop if dizzy.
CP18: amylase in germinating grains
Method recap (see Core practical 18, Unit 5): barley grains are cut in half (embryo halves removed) and soaked in different gibberellin concentrations, then placed cut side down on starch agar. After incubation, flood with iodine: clear zones show where amylase has digested starch.
- Area of clear zone = πr² (mean of two diameters).
- Sterilise grain surfaces (dilute bleach) and use aseptic technique, because microorganisms also make amylase.
- Controls: half-grains with no gibberellin; boiled grains.
- Analysis: scatter graph of mean zone area against gibberellin concentration and Spearman's rank.
Exam angles
- Read values from a trace with correct units (dm³ or cm³, per minute).
- Explain why the trace falls (oxygen used; CO₂ absorbed by soda lime).
- Explain why embryo halves are removed in CP18 (the embryo makes its own gibberellin).
Worked example
A spirometer trace shows breaths of 0.5 dm³ with 15 breaths per minute, and the trace falls by 0.9 dm³ over 3 minutes. Calculate minute ventilation and oxygen consumption.
- Ventilation = 0.5 x 15 = 7.5 dm³ min⁻¹
- O₂ consumption = 0.9 ÷ 3 = 0.3 dm³ min⁻¹
Answer: 7.5 dm³ min⁻¹ and 0.3 dm³ min⁻¹
Check yourself
- Tidal volume is 0.65 dm³ and breathing rate is 18 breaths per minute. Calculate minute ventilation.
Show answer
11.7 dm³ min⁻¹. 0.65 x 18 = 11.7 dm³ min⁻¹.
- A trace shows 7 breaths in 30 s. Calculate the breathing rate per minute.
Show answer
14 breaths per minute. 7 x 2 = 14 breaths per minute.
- A spirometer trace falls by 1.2 dm³ over 4 minutes. Calculate the rate of oxygen consumption in dm³ min⁻¹.
Show answer
0.3 dm³ min⁻¹. 1.2 / 4 = 0.3 dm³ min⁻¹.
- A clear zone around a half-grain has diameters of 11 mm and 13 mm. Using the mean diameter, calculate the area in mm² to 3 significant figures.
Show answer
113 mm². Mean diameter 12 mm, r = 6 mm; π x 36 = 113 mm².
- Why does a spirometer trace slope downwards over time?
- The volunteer breathes out more than in
- Oxygen is used by the volunteer and the CO₂ breathed out is absorbed by soda lime
- The chamber leaks oxygen
- Carbon dioxide builds up
Show answer
Oxygen is used by the volunteer and the CO₂ breathed out is absorbed by soda lime. Volume of gas in the chamber decreases.
- Why are the embryo halves of barley grains discarded in CP18?
- The embryo contains no starch
- The embryo is toxic
- The embryo would grow too quickly
- The embryo produces its own gibberellin, which would affect the results
Show answer
The embryo produces its own gibberellin, which would affect the results. Only added gibberellin should vary.
- What do clear zones on starch agar flooded with iodine show?
- Gibberellin has been destroyed
- Starch has been digested by amylase
- Glucose has been made into starch
- Bacteria have died
Show answer
Starch has been digested by amylase. No starch means no blue-black colour.
- Why are barley grains surface-sterilised before CP18?
- Microorganisms on the grains could produce amylase and digest starch
- To kill the aleurone cells
- To add gibberellin
- To soften the grain
Show answer
Microorganisms on the grains could produce amylase and digest starch. Contaminants would add amylase activity.
Sources
- Pearson Edexcel International Advanced Level in Biology specification (XBI11/YBI11, first teaching 2018): Unit 3, Unit 6 and Appendix 6 mathematical skills
- Pearson Examiners' Report WBI16/01, January 2024
Last updated 8 November 2026. Spotted a mistake? Tell us.