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Tests for organic functional groups (AS)
Edexcel IAL Chemistry · WCH13 Practical Skills in Chemistry I
Core Practical 8 includes organic tests. In the exam you must give the full reagent, the conditions, and the observation before and after, and name the group the test shows.
The AS tests
| Group | Reagent and conditions | Positive result |
|---|---|---|
| C=C (alkene) | bromine water, shake | orange to colourless |
| -OH (alcohol or carboxylic acid) | phosphorus(V) chloride, PCl5, dry | steamy fumes of hydrogen chloride |
| primary or secondary alcohol | acidified potassium dichromate(VI), warm | orange to green (tertiary: no change) |
| aldehyde | Fehling's or Benedict's solution, warm | blue solution to red precipitate |
| aldehyde | Tollens' reagent, warm in a water bath | silver mirror |
| carboxylic acid | sodium hydrogencarbonate solution | effervescence; CO2 turns limewater cloudy |
| halogenoalkane | warm with NaOH(aq), acidify with dilute HNO3, then add AgNO3(aq) (or warm with ethanolic AgNO3) | white (Cl), cream (Br) or yellow (I) precipitate |
Writing answers that score
- Give the full reagent name, including 'acidified' for dichromate(VI) or manganate(VII), and the condition (warm, water bath).
- Give the colour before and after, in the right order.
- Name the functional group, not an ion: the hydroxyl group is -OH, not OH- (June 2025 report).
- For PCl5 the gas is hydrogen chloride; the observation is steamy (misty) fumes.
- Do not add extra tests that contradict your answer.
Using tests to tell compounds apart
- Primary, secondary or tertiary alcohol: tertiary alcohols do not change the colour of acidified dichromate(VI). To separate primary from secondary, oxidise with distillation and test the distillate: an aldehyde (from a primary alcohol) gives a silver mirror with Tollens' or a red precipitate with Fehling's; a ketone does not.
- In the halogenoalkane test, acidify with nitric acid before adding silver nitrate, because excess OH- would precipitate silver oxide.
Worked example
How could you distinguish butan-1-ol, butan-2-ol and 2-methylpropan-2-ol?
- Warm each with acidified potassium dichromate(VI): 2-methylpropan-2-ol (tertiary) stays orange; the others turn green.
- Oxidise the other two with distillation and add Tollens' reagent to each distillate.
- Silver mirror: butanal, so the alcohol was butan-1-ol. No mirror: butanone, from butan-2-ol.
Answer: Dichromate picks out the tertiary alcohol; Tollens' on the distillate separates primary from secondary.
Check yourself
- What is observed when PCl5 is added to a dry alcohol?
- A silver mirror
- An orange precipitate
- Steamy fumes
- A colour change from orange to green
Show answer
Steamy fumes. Hydrogen chloride gas forms and fumes in moist air.
- What colour change is seen when a primary alcohol is warmed with acidified potassium dichromate(VI)?
- Orange to green
- Green to orange
- Purple to colourless
- Blue to red
Show answer
Orange to green. Cr2O72- (orange) is reduced to Cr3+ (green). Reversing the colours loses the mark.
- Which alcohol gives no colour change when warmed with acidified potassium dichromate(VI)?
- Propan-1-ol
- Propan-2-ol
- 2-methylpropan-2-ol
- Ethanol
Show answer
2-methylpropan-2-ol. Tertiary alcohols have no H on the carbon bearing the OH, so they resist oxidation.
- In the test for a halogenoalkane, why is dilute nitric acid added after warming with sodium hydroxide and before adding silver nitrate?
- To oxidise the halide ions
- To neutralise excess hydroxide ions, which would precipitate silver oxide
- To dissolve the halogenoalkane
- To act as a catalyst for the precipitation
Show answer
To neutralise excess hydroxide ions, which would precipitate silver oxide. OH- and Ag+ give a brown precipitate that would hide the result.
- What is the positive result for an aldehyde with Tollens' reagent?
- A red precipitate
- Steamy fumes
- Orange to colourless
- A silver mirror
Show answer
A silver mirror. Ag+ is reduced to silver metal on the glass.
- Which reagent gives effervescence with a carboxylic acid but not with an alcohol?
- Bromine water
- Sodium hydrogencarbonate solution
- Phosphorus(V) chloride
- Acidified potassium dichromate(VI)
Show answer
Sodium hydrogencarbonate solution. Acids react with hydrogencarbonate to give CO2; alcohols are too weakly acidic.
- Describe the test for a carbon-carbon double bond, including the result.
Show answer
Shake with bromine water; it turns from orange to colourless.. Bromine adds across C=C.
Sources
- Pearson Edexcel IAL Chemistry (2018) specification
- Pearson IAL Chemistry teacher practical guide
- Pearson examiners' report, WCH13 June 2025
- Pearson examiners' report, WCH13 October 2021
Last updated 8 November 2026. Spotted a mistake? Tell us.