All subjects · Chemistry · WCH14 (Unit 4)
Total entropy change and feasibility
A reaction is feasible when the total entropy change, of the system and its surroundings together, is positive. Temperature controls how much the surroundings count.
Entropy of the surroundings (spec 12.6, 12.8)
ΔStotal = ΔSsystem + ΔSsurroundings
ΔSsurroundings = -ΔH / T
Convert ΔH from kJ to J first. An exothermic reaction (ΔH negative) releases heat into the surroundings, so ΔSsurroundings is positive. The effect is larger at low temperature: the same amount of heat makes more difference to cold surroundings.
Feasibility (spec 12.9, 12.10)
A reaction is thermodynamically feasible when ΔStotal > 0, even if ΔSsystem or ΔSsurroundings is negative.
- Endothermic, ΔSsystem positive: feasible only above a certain temperature, found by setting ΔStotal = 0: T = ΔH / ΔSsystem (ΔH in J).
- Exothermic, ΔSsystem negative: feasible only below a certain temperature.
- Exothermic, ΔSsystem positive: feasible at all temperatures.
You may also meet ΔG = ΔH - TΔSsystem (feasible when ΔG < 0), which is the same idea multiplied by -T. It is not required.
Thermodynamic and kinetic stability (spec 12.11)
A positive ΔStotal says a reaction can happen, not how fast. If the activation energy is high, a feasible reaction may be too slow to notice: the reactants are kinetically stable (or kinetically inert). Methane and oxygen at room temperature, or diamond turning into graphite, are feasible but do not happen at a noticeable rate. A system is thermodynamically stable only when ΔStotal for its reaction is negative.
Worked example
CaCO3(s) -> CaO(s) + CO2(g): ΔH = +178 kJ mol-1, ΔSsystem = +160.4 J mol-1 K-1. Is it feasible at 298 K? Above what temperature is it feasible?
- ΔSsurroundings = -178 000 / 298 = -597.3 J mol-1 K-1
- ΔStotal = 160.4 - 597.3 = -436.9 J mol-1 K-1, so not feasible at 298 K
- T = ΔH / ΔSsystem = 178 000 / 160.4
Answer: Not feasible at 298 K; feasible above about 1110 K
Check yourself
- Calculate ΔSsurroundings at 298 K for the Haber process, ΔH = -92.0 kJ mol-1.
Show answer
+309 J mol-1 K-1. ΔSsurr = -(-92 000) / 298 = +309 J mol-1 K-1.
- For N2O4(g) -> 2NO2(g), ΔH = +57.2 kJ mol-1 and ΔSsystem = +175.8 J mol-1 K-1. Calculate ΔStotal at 298 K.
Show answer
-16.1 J mol-1 K-1. ΔSsurr = -57 200 / 298 = -191.9; ΔStotal = 175.8 + (-191.9) = -16.1 J mol-1 K-1, so it is not feasible at 298 K.
- A reaction has ΔH = +178 kJ mol-1 and ΔSsystem = +160.4 J mol-1 K-1. Calculate the minimum temperature at which it becomes feasible.
Show answer
1110 K. T = 178 000 / 160.4 = 1110 K.
- A reaction is exothermic and has a negative ΔSsystem. How does raising the temperature affect its feasibility?
- It becomes more feasible, because ΔSsystem increases
- It becomes less feasible, because the positive ΔSsurroundings gets smaller
- It has no effect
- It always becomes feasible
Show answer
It becomes less feasible, because the positive ΔSsurroundings gets smaller. -ΔH/T is positive but shrinks as T rises, so eventually ΔStotal becomes negative.
- Methane and oxygen do not react at room temperature, although ΔStotal is positive. What is the best description?
- The mixture is thermodynamically stable
- The reaction is endothermic
- ΔSsystem is too large
- The mixture is kinetically stable because the activation energy is high
Show answer
The mixture is kinetically stable because the activation energy is high. Feasible but very slow: a spark supplies the activation energy.
- Which combination gives a reaction that is feasible at every temperature?
- ΔH positive and ΔSsystem negative
- ΔH negative and ΔSsystem positive
- ΔH positive and ΔSsystem positive
- ΔH negative and ΔSsystem negative
Show answer
ΔH negative and ΔSsystem positive. Both ΔSsystem and ΔSsurroundings are positive, so ΔStotal is always positive.
- Why must ΔH in kJ mol-1 be multiplied by 1000 before calculating ΔSsurroundings?
- Temperature is in kelvin
- ΔH is always negative
- To make the answer positive
- Entropy values are in J mol-1 K-1
Show answer
Entropy values are in J mol-1 K-1. Mixing kJ and J gives an answer 1000 times too small.
Sources
- Pearson Edexcel IAL Chemistry (2018) specification
- Pearson Edexcel IAL Chemistry (2018) scheme of work
Last updated 7 November 2026. Spotted a mistake? Tell us.