All subjects · Further Mathematics · WFM01 Further Pure Mathematics 1

Equations with transformed roots

Edexcel IAL Further Mathematics · WFM01 Further Pure Mathematics 1

Given a quadratic with roots α and β, you can form a new quadratic whose roots are, say, α + 3 and β + 3, or α2 and β2, without ever finding α and β.

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Method

1. Find α + β and αβ from the original equation.

2. Find the sum of the new roots and the product of the new roots, in terms of α + β and αβ.

3. Write x2 - (new sum)x + (new product) = 0, then multiply to give integer coefficients.

Common transformations

Presentation

The answer is an equation: include "= 0", use integer coefficients, and do not drop the x term. Check one easy case if you can, for example by solving the original equation mentally when its roots are simple.

Worked example

α and β are the roots of 2x2 - 3x - 4 = 0. Find a quadratic equation with integer coefficients whose roots are α2 and β2.

  1. α + β = 3/2 and αβ = -2.
  2. New sum = (α + β)2 - 2αβ = 9/4 + 4 = 25/4. New product = (αβ)2 = 4.
  3. x2 - (25/4)x + 4 = 0; multiply by 4.

Answer: 4x2 - 25x + 16 = 0

Key idea: New sum and new product, in terms of α + β and αβ; then x2 - (sum)x + (product) = 0 with integer coefficients.

Check yourself

  1. α and β are the roots of 2x2 - 3x - 4 = 0. Find a quadratic with integer coefficients and roots α + 3 and β + 3. Give the left-hand side of the equation, with x2 coefficient 2.
    Show answer

    2x2 - 15x + 23. Sum = 3/2 + 6 = 15/2. Product = αβ + 3(α + β) + 9 = -2 + 9/2 + 9 = 23/2. x2 - (15/2)x + 23/2 = 0, so 2x2 - 15x + 23 = 0.

  2. Using the same α and β, give the left-hand side of the integer quadratic equation with roots α2 and β2, with x2 coefficient 4.
    Show answer

    4x2 - 25x + 16. Sum 25/4 and product 4 give x2 - (25/4)x + 4 = 0.

  3. Using the same α and β, give the left-hand side of the integer quadratic equation with roots 1/α and 1/β, with x2 coefficient 4.
    Show answer

    4x2 + 3x - 2. Sum = (α + β)/(αβ) = -3/4. Product = 1/(αβ) = -1/2. x2 + (3/4)x - 1/2 = 0, so 4x2 + 3x - 2 = 0.

  4. Using the same α and β, give the left-hand side of the integer quadratic equation with roots α3 and β3, with x2 coefficient 8.
    Show answer

    8x2 - 99x - 64. Sum = 99/8 (from the worked identity) and product = (αβ)3 = -8. x2 - (99/8)x - 8 = 0, so 8x2 - 99x - 64 = 0.

  5. Using the same α and β, give the left-hand side of the quadratic equation with roots 2α and 2β, with x2 coefficient 1.
    Show answer

    x2 - 3x - 8. Sum = 2(3/2) = 3. Product = 4αβ = -8. So x2 - 3x - 8 = 0.

  6. The roots of a quadratic are α and β. What is the product of the new roots α + 1 and β + 1?
    • αβ + 1
    • αβ + 2
    • αβ + (α + β) + 1
    • (α + β) + 2
    Show answer

    αβ + (α + β) + 1. (α + 1)(β + 1) = αβ + α + β + 1.

  7. A student's final answer is x2 - (25/4)x + 4. What should be improved?
    • Multiply by 4 to get integer coefficients and write = 0
    • Nothing: it is fully correct
    • Change the sign of the x term
    • Divide by 4 so the constant is 1
    Show answer

    Multiply by 4 to get integer coefficients and write = 0. The question asks for an equation with integer coefficients: 4x2 - 25x + 16 = 0.

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Last updated 8 November 2026. Spotted a mistake? Tell us.