All subjects · Mathematics · WMA11 (P1)
Surds and rationalising the denominator
A surd is a root that cannot be written as a whole number or fraction, such as sqrt(2). Exact answers in P1 are often given in surd form.
Simplifying
- sqrt(ab) = sqrt(a) x sqrt(b)
- sqrt(a/b) = sqrt(a) / sqrt(b)
Look for the largest square factor: sqrt(72) = sqrt(36) x sqrt(2) = 6sqrt(2). Like surds can then be collected: 6sqrt(2) + sqrt(2) = 7sqrt(2).
Rationalising a single surd
To remove sqrt(a) from the bottom, multiply top and bottom by sqrt(a):
6/sqrt(3) = 6sqrt(3)/3 = 2sqrt(3).
Rationalising a + sqrt(b)
Multiply top and bottom by the conjugate a - sqrt(b). The bottom becomes a difference of two squares: (a + sqrt(b))(a - sqrt(b)) = a2 - b, which has no surd.
Worked example
Rationalise 4/(3 - sqrt(5)).
- Multiply top and bottom by 3 + sqrt(5).
- Bottom: 9 - 5 = 4.
- Top: 4(3 + sqrt(5)).
- Divide by 4.
Answer: 3 + sqrt(5)
Check yourself
- Simplify sqrt(72).
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6√2. 72 = 36 x 2, so sqrt(72) = 6sqrt(2).
- Simplify sqrt(50) + sqrt(18).
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8√2. sqrt(50) = 5sqrt(2) and sqrt(18) = 3sqrt(2). Together: 8sqrt(2).
- Simplify sqrt(12) x sqrt(3).
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6. sqrt(12) x sqrt(3) = sqrt(36) = 6.
- Rationalise 6/sqrt(3).
- 6sqrt(3)
- sqrt(3)/2
- 18
- 2sqrt(3)
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2sqrt(3). 6/sqrt(3) x sqrt(3)/sqrt(3) = 6sqrt(3)/3 = 2sqrt(3).
- Expand and simplify (2 + sqrt(3))(2 - sqrt(3)).
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1. This is a difference of two squares: 4 - 3 = 1.
- Rationalise 1/(sqrt(5) - 2).
- sqrt(5) - 2
- (sqrt(5) + 2)/9
- (sqrt(5) + 2)/3
- sqrt(5) + 2
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sqrt(5) + 2. Multiply top and bottom by sqrt(5) + 2. The bottom is 5 - 4 = 1, so the answer is sqrt(5) + 2.
- (3 + sqrt(2))2 = a + b sqrt(2). Find a.
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11. (3 + sqrt(2))2 = 9 + 6sqrt(2) + 2 = 11 + 6sqrt(2), so a = 11.
- (3 + sqrt(2))2 = a + b sqrt(2). Find b.
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6. The middle terms are 3sqrt(2) + 3sqrt(2) = 6sqrt(2), so b = 6.
Sources
- Pearson Edexcel International Advanced Level in Mathematics specification (issue 3)
- Pearson Edexcel IAL Pure Mathematics 1 scheme of work
Last updated 7 November 2026. Spotted a mistake? Tell us.