All subjects · Mathematics · WMA13 (P3)
Inverse trigonometric functions
arcsin, arccos and arctan are the inverse functions of sin, cos and tan. Because those are many-one, their domains are restricted first.
Restricted domains
- arcsin x: domain -1 ≤ x ≤ 1, range -π/2 ≤ y ≤ π/2
- arccos x: domain -1 ≤ x ≤ 1, range 0 ≤ y ≤ π
- arctan x: domain x ∈ ℝ, range -π/2 < y < π/2
These ranges give the principal value your calculator shows.
Graphs
Each graph is the reflection in y = x of the restricted graph of sin, cos or tan. y = arctan x has horizontal asymptotes y = ±π/2.
Using them
arcsin(1/2) = π/6, because sin(π/6) = 1/2 and π/6 is in the range. To find sin(arccos(3/5)), draw a right-angled triangle with cos θ = 3/5: the opposite side is 4, so sin θ = 4/5.
Worked example
Find the exact value of arccos(-1/2).
- cos(π/3) = 1/2.
- cos is negative in the second quadrant, so use π - π/3.
- 2π/3 lies in the range 0 to π.
Answer: 2π/3
Check yourself
- Find the exact value of arcsin(-1/2).
- 7π/6
- 11π/6
- π/6
- -π/6
Show answer
-π/6. sin(-π/6) = -1/2 and -π/6 lies between -π/2 and π/2.
- Find arctan(1) in radians, to 3 decimal places.
Show answer
0.785. arctan(1) = π/4 = 0.785.
- What is the range of y = arccos x?
- -π/2 ≤ y ≤ π/2
- -1 ≤ y ≤ 1
- 0 ≤ y ≤ 2π
- 0 ≤ y ≤ π
Show answer
0 ≤ y ≤ π. cos is one-one on 0 to π, so that is the restricted domain of cos and the range of arccos.
- Why must the domain of sin x be restricted before defining arcsin x?
- sin x is many-one, so it must be made one-one
- sin x is not continuous
- sin x has asymptotes
- sin x can be negative
Show answer
sin x is many-one, so it must be made one-one. Only one-one functions have inverses.
- Find the exact value of sin(arccos(3/5)). Give your answer as a fraction in its simplest form.
Show answer
4/5. Let θ = arccos(3/5). A 3, 4, 5 triangle gives sin θ = 4/5, positive because θ is between 0 and π.
- What is the domain of y = arcsin x?
- -1 ≤ x ≤ 1
- -π/2 ≤ x ≤ π/2
- x ∈ ℝ
- 0 ≤ x ≤ π
Show answer
-1 ≤ x ≤ 1. The inputs of arcsin are the outputs of sin, which lie between -1 and 1.
- Solve arctan(2x - 1) = π/4.
Show answer
1. 2x - 1 = tan(π/4) = 1, so x = 1.
- Solve arccos x = 1, where the angle is in radians. Give x to 3 decimal places.
Show answer
0.540. x = cos 1 = 0.540 (calculator in radians).
Sources
- Pearson Edexcel International Advanced Level in Mathematics specification (issue 3)
- Pearson Edexcel IAL Pure Mathematics 3 scheme of work
Last updated 7 November 2026. Spotted a mistake? Tell us.