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Two-tailed tests
Edexcel IAL Mathematics · WST02 Statistics 2
When the question asks whether a parameter has changed, without saying which way, the test is two-tailed and the significance level is split between the two tails.
Splitting α
For a two-tailed test at level α, H1 uses ≠ and there are two critical regions, one in each tail. Each tail has probability as close as possible to α/2 without exceeding it. At 5% each tail is at most 0.025; at 10%, at most 0.05. Pearson mark schemes follow this even when a bigger tail is nearer to α/2: for Po(10) at 5% (June 2025) the lower region is X ≤ 3 (0.0103), not X ≤ 4 (0.0293). If a question states its own rule for the tails, follow the question. A common error, noted by examiners, is to use α rather than α/2 in each tail.
Example
H0: p = 0.4, H1: p ≠ 0.4, n = 20, 5% level.
Lower tail: P(X ≤ 3) = 0.0160, P(X ≤ 4) = 0.0510, so X ≤ 3.
Upper tail: P(X ≥ 13) = 1 - 0.9790 = 0.0210, P(X ≥ 12) = 1 - 0.9435 = 0.0565, so X ≥ 13.
Critical region: X ≤ 3 or X ≥ 13. Actual significance level = 0.0160 + 0.0210 = 0.0370.
Using a probability instead
With an observed value x, decide which tail it is in (compare x with the mean np), find the probability of that tail (P(X ≥ x) if x is above the mean, P(X ≤ x) if below), and compare it with α/2.
Worked example
H0: p = 0.4, H1: p ≠ 0.4, n = 20. The observed value is 13. Test at the 5% level.
- The mean is 8, so 13 is in the upper tail.
- P(X ≥ 13) = 0.0210
- 0.0210 < 0.025, so reject H0.
Answer: There is evidence that the proportion has changed.
Check yourself
- H0: p = 0.4, H1: p ≠ 0.4, n = 20, 5% level. The lower critical region is X ≤ c. Find c.
Show answer
3. P(X ≤ 3) = 0.0160 ≤ 0.025 but P(X ≤ 4) = 0.0510 > 0.025.
- H0: p = 0.4, H1: p ≠ 0.4, n = 20, 5% level. The upper critical region is X ≥ d. Find d.
Show answer
13. P(X ≥ 13) = 0.0210 ≤ 0.025 but P(X ≥ 12) = 0.0565 > 0.025.
- For the critical region X ≤ 3 or X ≥ 13 with X ~ B(20, 0.4), find the actual significance level. Give your answer to 4 decimal places.
Show answer
0.0370. 0.0160 + 0.0210 = 0.0370.
- H0: p = 0.4, H1: p ≠ 0.4, n = 20. The observed value is 4. Find P(X ≤ 4) under H0. Give your answer to 4 decimal places.
Show answer
0.0510. P(X ≤ 4) = 0.0510.
- In the two-tailed 5% test above, P(X ≤ 4) = 0.0510. What is the decision?
- Reject H0, because the probability is less than 0.05
- Reject H0, because 4 is below the mean
- Do not reject H0, because the probability is more than 0.025
- Do not reject H0, because the probability is less than 0.5
Show answer
Do not reject H0, because the probability is more than 0.025. Compare a single tail with α/2 = 0.025.
- A two-tailed test is carried out at the 10% level. What is the largest probability allowed in each tail?
- 0.05
- 0.1
- 0.025
- 0.2
Show answer
0.05. α/2 = 0.05.
- In a two-tailed test, the observed value is above the mean. Which probability should be compared with α/2?
- P(X ≤ observed value)
- P(X = observed value)
- P(X ≥ observed value)
- P(X ≥ mean)
Show answer
P(X ≥ observed value). Use the tail that contains the observed value: values at least as extreme.
Sources
- Pearson Edexcel International Advanced Level in Mathematics specification (issue 3), Unit S2
- Pearson Edexcel IAL Statistics S2 (WST02) examiners' report, October 2024
- Pearson Edexcel IAL Statistics S2 (WST02) mark scheme, October 2024 (copy hosted by Physics and Maths Tutor)
Last updated 8 November 2026. Spotted a mistake? Tell us.