All subjects · Physics · WPH11 (Unit 1)
Stress-strain graphs and breaking stress
Stress-strain graphs describe a material rather than one particular sample, so you can compare steel, copper, glass and rubber directly.
Why stress and strain?
A force-extension graph depends on the sample's length and thickness. Stress (F/A) and strain (Δx/x) remove those effects, so a stress-strain graph is the same for every sample of a material. (See the lesson on stress, strain and the Young modulus for the definitions.)
Features of the graph
- Straight-line section: gradient = Young modulus E
- Limit of proportionality and elastic limit, as on force-extension graphs
- Yield point(s): large strain for little extra stress
- Ultimate tensile stress (UTS): the maximum stress the material can take
- Breaking stress: the stress at which the material breaks (fractures)
Types of material
- Brittle (glass, cast iron, ceramics): a straight line almost to the breaking point; little or no plastic deformation, so it snaps suddenly.
- Ductile (copper, mild steel): large plastic deformation before breaking; can be drawn into wires.
- Polymeric (rubber): large strains, with a non-linear graph.
A material is strong if its breaking stress is high and stiff if its Young modulus is high.
(Brittle, ductile and ultimate tensile stress are useful background but are not named in the IAL specification; exam questions focus on breaking stress.)
Worked example
A wire of cross-sectional area 2.0 x 10-7 m2 breaks under a tension of 90 N. Find its breaking stress.
- Breaking stress = breaking force / area
- = 90 / (2.0 x 10-7)
Answer: Breaking stress = 4.5 x 108 Pa
Check yourself
- A steel wire of diameter 0.50 mm breaks under a tension of 200 N. Find its breaking stress in GPa, to 3 s.f.
Show answer
1.02 GPa. A = π(0.25 x 10-3)2 = 1.96 x 10-7 m2; stress = 200 / 1.96 x 10-7 = 1.02 x 109 Pa = 1.02 GPa.
- A wire of cross-sectional area 1.0 x 10-6 m2 has a breaking stress of 4.0 x 108 Pa. Find the largest tension it can take, in N.
Show answer
400 N. F = stress x area = 4.0 x 108 x 1.0 x 10-6 = 400 N.
- On a stress-strain graph, the straight section passes through a stress of 1.2 x 108 Pa at a strain of 0.0016. Find the Young modulus in GPa.
Show answer
75 GPa. E = 1.2 x 108 / 0.0016 = 7.5 x 1010 Pa = 75 GPa.
- Which describes a brittle material?
- It can be drawn out into long wires
- It breaks with little or no plastic deformation
- It has a very low Young modulus
- It stretches a lot before breaking
Show answer
It breaks with little or no plastic deformation. Brittle materials such as glass snap without first deforming plastically.
- Which material is ductile?
- Glass
- Cast iron
- Concrete
- Copper
Show answer
Copper. Copper undergoes large plastic deformation and can be drawn into wires.
- What is the ultimate tensile stress of a material?
- The stress at the limit of proportionality
- The maximum stress it can withstand
- The stress at which it starts to deform
- Its Young modulus
Show answer
The maximum stress it can withstand. UTS is the highest point on the stress-strain graph.
- Why do engineers compare materials using stress-strain graphs rather than force-extension graphs?
- Force-extension graphs cannot show the elastic limit
- Stress-strain graphs are always straight lines
- Force cannot be measured accurately
- Stress-strain graphs do not depend on the size of the sample
Show answer
Stress-strain graphs do not depend on the size of the sample. Dividing by area and original length removes the effect of sample dimensions.
Sources
- Pearson Edexcel International Advanced Subsidiary/Advanced Level in Physics specification (XPH11/YPH11), Issue 3
- Pearson qualifications: International Advanced Levels Physics (2018)
Last updated 7 November 2026. Spotted a mistake? Tell us.