All subjects · Physics · WPH12 (Unit 2)
Core practical 7: measuring resistivity
Core practical 7 finds the resistivity of a material, usually a metal wire, using R = ρl / A. (The equation itself is introduced in the lesson on the wave equation and resistivity.)
Method
- Measure the wire's diameter with a micrometer at several points and orientations; find the mean and A = πd2/4.
- Tape the wire along a metre rule. Connect one end in a circuit with an ammeter, and use a flying lead (crocodile clip) to make contact at different lengths l.
- Connect a voltmeter across the length l. For each length, record V and I and calculate R = V / I (or use an ohmmeter).
- Use at least six lengths.
Analysis
R = ρl / A, so a graph of R (y-axis) against l (x-axis) is a straight line with gradient ρ / A. Therefore ρ = gradient x A. Contact resistance at the clips adds a constant to every reading: it shifts the line up (an intercept) but does not change the gradient.
Good practice
- Keep the current small, and switch off between readings, so the wire does not heat up (resistance rises with temperature).
- Measure the diameter carefully: it is squared, so its percentage uncertainty is doubled in A.
- Use a long wire to make R large enough to measure precisely.
Worked example
A graph of R against l has gradient 2.6 Ω/m. The wire's diameter is 0.30 mm. Find ρ.
- A = π(0.15 x 10-3)2 = 7.07 x 10-8 m2
- ρ = gradient x A = 2.6 x 7.07 x 10-8
Answer: ρ = 1.8 x 10-7 Ω m
Check yourself
- The gradient of a graph of R against l is 8.0 Ω/m, and the wire's cross-sectional area is 1.5 x 10-7 m2. Find ρ, in units of 10-6 Ω m.
Show answer
1.2 x 10-6 Ω m. ρ = gradient x A = 8.0 x 1.5 x 10-7 = 1.2 x 10-6 Ω m.
- A constantan wire (ρ = 4.9 x 10-7 Ω m) is 0.80 m long with a diameter of 0.40 mm. Find its resistance in Ω, to 3 s.f.
Show answer
3.12 Ω. A = π(0.20 x 10-3)2 = 1.26 x 10-7 m2; R = 4.9 x 10-7 x 0.80 / 1.26 x 10-7 = 3.12 Ω.
- What length of nichrome wire (ρ = 1.1 x 10-6 Ω m, A = 2.0 x 10-7 m2) has a resistance of 11 Ω? Answer in m.
Show answer
2 m. l = RA / ρ = 11 x 2.0 x 10-7 / 1.1 x 10-6 = 2.0 m.
- Why is ρ found from the gradient of R against l rather than from a single reading?
- The gradient is not affected by contact resistance and averages out random errors
- A single reading cannot be calculated
- The gradient gives the area directly
- It makes the wire cooler
Show answer
The gradient is not affected by contact resistance and averages out random errors. Constant contact resistance only shifts the line up; the gradient uses all the data.
- Why should the current be kept small?
- To protect the voltmeter
- To make the wire longer
- To stop the wire heating up and changing its resistance
- To reduce the resistivity
Show answer
To stop the wire heating up and changing its resistance. A temperature rise increases the resistance of a metal.
- A wire is replaced by one of the same material and length but half the diameter. What happens to its resistance?
- It becomes 4 times as large
- It doubles
- It halves
- It stays the same
Show answer
It becomes 4 times as large. Halving d makes A a quarter, and R = ρl / A, so R is 4 times larger.
- What is the unit of resistivity?
- Ω/m
- Ω m2
- Ω m
- Ω
Show answer
Ω m. ρ = RA / l has units Ω x m2 / m = Ω m.
Sources
- Pearson Edexcel International Advanced Subsidiary/Advanced Level in Physics specification (XPH11/YPH11), Issue 3
- Pearson qualifications: International Advanced Levels Physics (2018)
- Cognito: Edexcel International A level Physics specification and core practicals
Last updated 7 November 2026. Spotted a mistake? Tell us.