All subjects · Physics · WPH13 Practical Skills in Physics I

Practical skills in core practicals 1 to 3

Edexcel IAL Physics · WPH13 Practical Skills in Physics I

This lesson applies Unit 3 skills to the Unit 1 core practicals: free fall, viscosity and the Young modulus. Revise the methods in the Unit 1 lessons on each core practical first.

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Core practical 1: free fall

Core practical 2: viscosity

Core practical 3: Young modulus

Worked example

A graph of force against extension for a 2.00 m wire of diameter 0.38 mm has gradient 1.10 x 104 N/m. Find E.

  1. A = π(0.38 x 10-3)2 / 4 = 1.134 x 10-7 m2 (keep this unrounded value in the calculator)
  2. E = gradient x l / A = 1.10 x 104 x 2.00 / 1.134 x 10-7 = 1.94 x 1011 Pa

Answer: E = 1.94 x 1011 Pa, close to the value for steel

Key idea: CP1: h against t2, gradient g/2, intercept reveals a release delay. CP2: equal times between band pairs show terminal velocity; diameter squared. CP3: long thin wire; E = gradient x l / A.

Check yourself

  1. In core practical 1, a graph of h against t2 has gradient 4.85 m/s2. Find g in m/s2.
    Show answer

    9.70 m/s2. g = 2 x gradient = 9.70 m/s2.

  2. How can a student show that a falling ball has reached terminal velocity in core practical 2?
    • Measure its speed once near the bottom
    • Use a longer tube
    • Time it between two pairs of equally spaced marks and check the times are equal
    • Check that the ball has stopped accelerating by eye
    Show answer

    Time it between two pairs of equally spaced marks and check the times are equal. Equal times over equal distances show the speed is constant.

  3. A ball falls between two bands 0.100 m apart in 1.25 s. Find its speed in m/s, to 3 s.f.
    Show answer

    0.0800 m/s. v = 0.100 / 1.25 = 0.0800 m/s.

  4. A 1.80 m wire has cross-sectional area 1.00 x 10-7 m2. Its force-extension graph has gradient 1.20 x 104 N/m. Find E, in units of 1011 Pa, to 3 s.f.
    Show answer

    2.16 x 1011 Pa. E = 1.20 x 104 x 1.80 / 1.00 x 10-7 = 2.16 x 1011 Pa.

  5. A wire's diameter is 0.38 mm, measured with a micrometer of resolution 0.01 mm. Find the percentage uncertainty in the diameter, using half the resolution, to 2 s.f.
    Show answer

    1.3 %. Uncertainty = 0.005 mm; 0.005 / 0.38 x 100 = 1.3%.

  6. Why is a long, thin wire used in core practical 3?
    • It is less likely to snap
    • It makes the Young modulus larger
    • It removes the need to measure the diameter
    • It gives a larger extension, so a smaller percentage uncertainty in the extension
    Show answer

    It gives a larger extension, so a smaller percentage uncertainty in the extension. Extension is proportional to length and inversely proportional to area, so a long thin wire stretches more for the same load.

  7. In core practical 1, the electromagnet releases the ball slightly after the timer starts. What effect does this have on g calculated from single readings using g = 2h/t2?
    • Every value of g is too large
    • Every value of g is too small
    • The values scatter randomly
    • There is no effect
    Show answer

    Every value of g is too small. Each measured t is too long, so 2h/t2 is too small: a systematic error.

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Last updated 8 November 2026. Spotted a mistake? Tell us.