All subjects · Physics · WPH16 Practical Skills in Physics II
Practical skills in core practical 11
Edexcel IAL Physics · WPH16 Practical Skills in Physics II
Applying Unit 6 skills to capacitor charge and discharge. Revise the Unit 4 lesson on core practical 11 first.
Collecting the data
- Use a data logger with a voltage sensor (high sampling rate for small RC), or an oscilloscope with a square-wave supply for RC of milliseconds.
- For hand timing, choose R and C so RC is tens of seconds, and read V at regular intervals.
- Fully charge before each discharge; use the same starting p.d.
Analysing it
- Quick estimate: RC is the time to fall to 37% of V_0 (or the time to halve divided by ln 2).
- Better: plot ln (V / V) against t / s. Gradient = -1/RC; intercept = ln V_0. A straight line confirms exponential discharge, and using all the points reduces random error.
- Compare RC with the nominal value from the labels. Capacitors often have tolerances of ± 10% or ± 20%, so use percentage difference or check against the tolerance range.
Safety
Give precautions specific to capacitors:
- discharge the capacitor fully before handling it;
- do not exceed its working (rated) p.d.;
- connect an electrolytic capacitor the right way round (correct polarity), as reverse connection can make it fail.
Insulating gloves are not accepted for ordinary laboratory power supplies.
Worked example
A 470 μF capacitor discharges through a 47 kΩ resistor. The measured RC is 19.8 s. Is this consistent with the labels if C has a ± 20% tolerance?
- Nominal RC = 470 x 10-6 x 47 x 103 = 22.1 s
- Percentage difference = |19.8 - 22.1| / 22.1 x 100 = 10%
- This is well within the 20% tolerance of C.
Answer: Yes: the result is consistent with the labelled values
Check yourself
- Find the nominal time constant of a 220 μF capacitor with a 100 kΩ resistor, in s.
Show answer
22 s. RC = 220 x 10-6 x 1.00 x 105 = 22 s.
- A capacitor charged to 9.0 V discharges. What p.d. marks one time constant, in V, to 2 s.f.?
Show answer
3.3 V. V = 9.0 x e-1 = 3.31 V (37% of 9.0 V).
- The p.d. across a discharging capacitor halves in 15.2 s. Find RC in s, to 3 s.f.
Show answer
21.9 s. RC = 15.2 / ln 2 = 21.9 s.
- A capacitor at 6.0 V discharges with RC = 22 s. Find the p.d. after 30 s, in V, to 2 s.f.
Show answer
1.5 V. V = 6.0 e-30/22 = 1.53 V.
- A graph of ln (V / V) against t / s has gradient -0.0455 s-1. Find C in μF if R = 22 kΩ, to 3 s.f.
Show answer
999 μF. RC = 1 / 0.0455 = 21.98 s; C = 21.98 / 22000 = 999 μF.
- Which precaution is specific to an experiment with an electrolytic capacitor?
- Wear insulating gloves with a laboratory supply
- Wear a lab coat
- Connect it with the correct polarity and do not exceed its working p.d.
- Work in a darkened room
Show answer
Connect it with the correct polarity and do not exceed its working p.d.. Reverse polarity or over-voltage can make an electrolytic capacitor fail.
- When is an oscilloscope with a square-wave supply better than hand timing for capacitor discharge?
- When RC is only a few milliseconds
- When RC is several minutes
- When the capacitor is uncharged
- When there is no resistor
Show answer
When RC is only a few milliseconds. Changes over milliseconds are far too fast to read by hand.
Sources
- Pearson Edexcel International Advanced Subsidiary/Advanced Level in Physics specification (XPH11/YPH11), Issue 3
- Pearson qualifications: International Advanced Levels Physics (2018)
- Pearson examiners' report: IAL Physics WPH16/01, June 2024
Last updated 8 November 2026. Spotted a mistake? Tell us.