All subjects · Physics · WPH16 Practical Skills in Physics II
Precision, accuracy, resolution, sensitivity and validity
Edexcel IAL Physics · WPH16 Practical Skills in Physics II
Unit 6 explicitly tests the language of measurement. Each word has a precise meaning, and examiners do not accept one in place of another.
The definitions
Pearson's practical appendix, and the Unit 6 specification, use these terms precisely:
| Term | Meaning |
|---|---|
| Accuracy | How close a measurement is to the true value. Affected by random and systematic errors. |
| Precision | How close repeated measurements are to each other. Affected only by random errors. |
| Repeatability | Precision when the same person repeats the same method with the same apparatus. |
| Reproducibility | Precision when different people, methods or apparatus are used: a harder test. |
| Resolution | The smallest measuring interval an instrument can show. |
| Sensitivity | The change in an instrument's output per unit change in the quantity being measured. |
| Validity | Whether a measurement or experiment actually measures what it is meant to. |
| Uncertainty | The interval in which the true value is expected to lie. |
Sensitivity in practice
A sensor or circuit is more sensitive if a small change in the input gives a large change in the output. For a thermistor potential divider, sensitivity = change in output p.d. / change in temperature (in V/K or mV/K). On a calibration curve, the sensitivity at a point is the gradient there, and it is usually greatest where the curve is steepest. A sensitive instrument is not necessarily accurate: it can respond strongly and still be wrongly calibrated.
Using the words correctly
- Justify an instrument by its resolution, not by saying it is 'more accurate' or 'more precise'.
- Results scattered tightly but offset from the true value are precise but not accurate.
- A result whose limits include the accepted value is accurate.
- A method is valid if it controls the variables that matter and measures the intended quantity.
Worked example
A thermistor circuit's output rises from 2.10 V at 30 °C to 2.58 V at 40 °C. Find the average sensitivity over this range.
- Sensitivity = change in output / change in input
- = (2.58 - 2.10) / (40 - 30) = 0.048 V/K
Answer: 48 mV/K
Check yourself
- A sensor's output changes by 0.84 V when the temperature rises by 20 K. Find its sensitivity in mV/K.
Show answer
42 mV/K. 0.84 / 20 = 0.042 V/K = 42 mV/K.
- Which statement defines precision?
- How close repeated measurements are to each other
- How close a measurement is to the true value
- The smallest interval an instrument can show
- The change in output per unit change in input
Show answer
How close repeated measurements are to each other. Precision is about the spread of repeats.
- A student's value of g has limits 9.70 m/s2 to 9.90 m/s2. The accepted value is 9.81 m/s2. Which word describes the result?
- Sensitive
- Reproducible
- Accurate
- Valid only
Show answer
Accurate. The accepted value lies within the limits, so the result is accurate.
- On the calibration curve for a thermistor circuit, where is the circuit most sensitive?
- Where the curve is flattest
- Where the curve is steepest
- At the lowest temperature always
- Where the output p.d. is largest
Show answer
Where the curve is steepest. Sensitivity is the gradient: the steepest part gives the largest output change per kelvin.
- Several different students using different apparatus all get similar values. What does this show?
- The result is repeatable only
- The instruments have high resolution
- The result is sensitive
- The result is reproducible
Show answer
The result is reproducible. Agreement across different operators and apparatus is reproducibility.
- A student justifies using digital calipers by saying 'they are more precise'. What would examiners prefer?
- They are more accurate
- Their resolution is 0.01 mm, so the percentage uncertainty is small
- They are more sensitive
- They are digital
Show answer
Their resolution is 0.01 mm, so the percentage uncertainty is small. Examiners do not accept precision or accuracy as substitutes for resolution.
- A light sensor's output rises from 1.25 V to 1.85 V when the illumination increases from 200 lux to 500 lux. Find its average sensitivity in mV per lux.
Show answer
2.0 mV per lux. 0.60 V / 300 lux = 0.0020 V/lux = 2.0 mV per lux.
Sources
- Pearson Edexcel International Advanced Subsidiary/Advanced Level in Physics specification (XPH11/YPH11), Issue 3
- Pearson qualifications: International Advanced Levels Physics (2018)
- Pearson Edexcel A level Physics: Appendix 10, Uncertainties and practical work
- Pearson examiners' report: IAL Physics WPH16/01, June 2024
- Pearson examiners' report: IAL Physics WPH13/01, October 2024
Last updated 8 November 2026. Spotted a mistake? Tell us.