All subjects · Chemistry · WCH14 (Unit 4)
Proton NMR: chemical shift, integration and splitting
Proton (1H) NMR gives three pieces of information: where the hydrogen atoms are (chemical shift), how many there are in each environment (peak area) and how many hydrogens are on the next carbon (splitting).
Chemical shift (spec 15.20 i)
Each peak is a different proton environment, measured relative to TMS at δ 0. Approximate shifts (data booklet values apply in the exam):
| Proton environment | δ / ppm |
|---|---|
| R-CH3, R-CH2-R | about 0.8 to 1.5 |
| H-C next to C=O | about 2.0 to 2.7 |
| H-C-O (alcohols, esters) | about 3.3 to 4.3 |
| R-OH (variable) | about 1 to 5 |
| arene ring H | about 6.5 to 8.0 |
| aldehyde -CHO | about 9 to 10 |
| carboxylic acid -COOH | about 10 to 12 |
Peak areas (spec 15.20 ii)
The area under each peak (shown by an integration trace or given as a ratio) is proportional to the number of hydrogen atoms in that environment. Ethanol, CH3CH2OH, gives a ratio 3 : 2 : 1.
Splitting: the n + 1 rule (spec 15.20 iii, iv)
In a high-resolution spectrum, a peak is split by the protons on adjacent carbon atoms that are in a different environment. n neighbouring H gives n + 1 lines:
- 0 neighbours: singlet; 1: doublet; 2: triplet; 3: quartet
An ethyl group, -CH2CH3, shows a quartet (CH2, next to CH3) and a triplet (CH3, next to CH2). O-H protons usually appear as singlets and do not split neighbouring peaks. Equivalent protons do not split each other.
Why TMS?
TMS gives a single strong peak because all 12 hydrogens are equivalent, its peak is away from most others, and it is inert and volatile, so it is easily removed.
Worked example
Predict the high-resolution 1H NMR spectrum of ethyl ethanoate, CH3COOCH2CH3.
- CH3CO-: 3H, no neighbouring H, singlet near δ 2.0
- -OCH2-: 2H, next to CH3, quartet near δ 4.1
- -CH2CH3: 3H, next to CH2, triplet near δ 1.3
Answer: Three peaks, ratio 3 : 2 : 3: singlet, quartet, triplet
Check yourself
- In the 1H NMR spectrum of chloroethane, CH3CH2Cl, how is the CH2 peak split?
- Triplet
- Doublet
- Singlet
- Quartet
Show answer
Quartet. The CH2 has 3 neighbouring H on the CH3: 3 + 1 = 4 lines.
- What is the peak area ratio in the 1H NMR spectrum of propanoic acid, CH3CH2COOH?
- 3 : 3 : 1
- 3 : 2 : 1
- 2 : 2 : 2
- 1 : 1 : 1
Show answer
3 : 2 : 1. CH3 (3H), CH2 (2H), COOH (1H).
- A 1H NMR spectrum has a peak at δ 9.7. Which group is present?
- A CH3 next to C=O
- An alkane CH3
- An alcohol C-H
- An aldehyde -CHO
Show answer
An aldehyde -CHO. Aldehyde protons appear at about 9 to 10 ppm.
- How many peaks are in the low-resolution 1H NMR spectrum of propan-2-ol, (CH3)2CHOH?
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3. Six equivalent CH3 protons, one CH proton and one OH proton: 3 environments.
- In the 1H NMR spectrum of 2-methylpropane, (CH3)3CH, how is the peak for the nine CH3 protons split?
- Singlet
- Triplet
- Doublet
- Decet
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Doublet. Each CH3 is next to a carbon with one H: 1 + 1 = 2 lines.
- A compound C3H6O has a single peak in its 1H NMR spectrum. What is it?
- Propanone
- Propanal
- Propan-1-ol
- Prop-2-en-1-ol
Show answer
Propanone. Propanone, CH3COCH3, has six equivalent protons.
- Why is TMS chosen as the reference in 1H NMR?
- It absorbs at the highest chemical shift
- It contains carbon-13 only
- Its 12 equivalent protons give one strong peak, and it is inert and volatile
- It reacts with the sample to make it visible
Show answer
Its 12 equivalent protons give one strong peak, and it is inert and volatile. A single, sharp, well-separated peak and easy removal.
Sources
- Pearson Edexcel IAL Chemistry (2018) specification
- Pearson Edexcel IAL Chemistry (2018) scheme of work
Last updated 7 November 2026. Spotted a mistake? Tell us.