All subjects · Physics · WPH14 (Unit 4)
Elastic and inelastic collisions; E_k = p2/2m
Momentum is always conserved when no external force acts, but kinetic energy is not. Checking the kinetic energy tells you what kind of collision happened.
Elastic or inelastic?
- Elastic: total kinetic energy is conserved.
- Inelastic: total kinetic energy decreases. The lost kinetic energy is transferred to thermal energy, sound and deformation.
- Totally inelastic: the objects stick together, giving the largest possible loss of kinetic energy.
Total energy and momentum are conserved in every case. To decide, calculate the total E_k before and after.
Kinetic energy from momentum
Since p = mv, v = p / m. Substituting into E_k = (1/2)mv2:
E_k = (1/2)m(p/m)2 = p2 / 2m
This works for non-relativistic particles (speeds much less than c). It is useful in particle physics, where momentum is often what you know.
A useful consequence
Two objects with the same momentum do not have the same kinetic energy: the one with the smaller mass has the larger E_k. In an explosion from rest, the lighter fragment carries away more of the kinetic energy.
Worked example
A 2.0 kg trolley at 3.0 m/s hits a stationary 1.0 kg trolley and they stick together. Is the collision elastic?
- Momentum: 6.0 = 3.0v, so v = 2.0 m/s
- E_k before = 0.5 x 2.0 x 3.02 = 9.0 J
- E_k after = 0.5 x 3.0 x 2.02 = 6.0 J
Answer: Inelastic: 3.0 J of kinetic energy is transferred to other stores
Check yourself
- An object of mass 4.0 kg has momentum 12 kg m/s. Find its kinetic energy in J.
Show answer
18 J. E_k = p2 / 2m = 144 / 8.0 = 18 J.
- An electron has momentum 2.0 x 10-24 kg m/s. Find its kinetic energy in eV, to 3 s.f.
Show answer
13.7 eV. E_k = (2.0 x 10-24)2 / (2 x 9.11 x 10-31) = 2.20 x 10-18 J; divide by 1.60 x 10-19 to get 13.7 eV.
- A proton has kinetic energy 3.2 x 10-13 J. Find its momentum, in units of 10-20 kg m/s, to 3 s.f.
Show answer
3.27 x 10-20 kg m/s. p = sqrt(2mE_k) = sqrt(2 x 1.67 x 10-27 x 3.2 x 10-13) = 3.27 x 10-20 kg m/s.
- A 0.50 kg trolley at 6.0 m/s hits a stationary 1.0 kg trolley and they stick together. How much kinetic energy is lost, in J?
Show answer
6 J. v = 3.0 / 1.5 = 2.0 m/s. E_k before = 9.0 J; after = 0.5 x 1.5 x 4.0 = 3.0 J; lost = 6.0 J.
- A 1.0 kg ball at 4.0 m/s hits a stationary 3.0 kg ball. Afterwards the 1.0 kg ball rebounds at 2.0 m/s and the 3.0 kg ball moves forward at 2.0 m/s. What type of collision is this?
- Inelastic
- Totally inelastic
- Elastic
- Impossible, because momentum is not conserved
Show answer
Elastic. Momentum: 4.0 = -2.0 + 6.0. E_k before = 8.0 J; after = 2.0 + 6.0 = 8.0 J. Kinetic energy is conserved.
- In a collision with no external forces, which quantity is always conserved?
- Total momentum
- Total kinetic energy
- The speed of each object
- The velocity of each object
Show answer
Total momentum. Momentum is conserved in every collision; kinetic energy only in elastic ones.
- A light particle and a heavy particle have the same momentum. Which has more kinetic energy?
- The heavy particle
- They have the same kinetic energy
- The light particle
- It depends on their directions
Show answer
The light particle. E_k = p2 / 2m, so with p fixed a smaller m gives a larger E_k.
Sources
- Pearson Edexcel International Advanced Subsidiary/Advanced Level in Physics specification (XPH11/YPH11), Issue 3
- Pearson qualifications: International Advanced Levels Physics (2018)
- Pearson Edexcel IAL Physics Unit 4 (WPH14) question paper, June 2024: list of data, formulae and relationships
Last updated 7 November 2026. Spotted a mistake? Tell us.